Guys.
I am using JDeveloper with Oracle AS .........
I have written a EJB QL like this
Select object(o) from Countries o where o.countryName like ?1
whenever I am tyring to run my app, it is throwing this exception
05/07/25 15:09:52 Encountered "o . countryName like ?1" at line 1, column 7.
Was expecting one of:
"(" ...
"NOT" ...
"IdentificationVar" "." "CmpField" "NOT" ...
"IdentificationVar" "." "CmpField" "IN" ...
"IdentificationVar" "." "CmpField" "LIKE" <CHAR_LITERAL> ...
"IdentificationVar" "." "CmpField" "LIKE" <STRING_LITERAL> ...
"IdentificationVar" "." "CmpField" "IS" ...
"+" ...
"-" ...
"IdentificationVar" "." "CmpField" "*" ...
"IdentificationVar" "." "CmpField" "/" ...
"IdentificationVar" "." "CmpField" "+" ...
"IdentificationVar" "." "CmpField" "-" ...
"IdentificationVar" "." "CmpField" "BETWEEN" ...
"IdentificationVar" "." "SingleValuedCmrField" ...
"IdentificationVar" "." "CollectionValuedCmrField" ...
"IdentificationVar" "NOT" ...
"IdentificationVar" "MEMBER" ...
"IdentificationVar" "." "CmpField" "=" ...
"IdentificationVar" "." "CmpField" ">" ...
"IdentificationVar" "." "CmpField" ">=" ...
"IdentificationVar" "." "CmpField" "<" ...
"IdentificationVar" "." "CmpField" "<=" ...
"IdentificationVar" "." "CmpField" "<>" ...
EJB QL statement : 'Select object(o) from Countries o where o.countryName like ?1'
EJB QL method : public abstract java.util.Collection model.CountriesHome.findByCountryName(java.lang.String) throws javax.ejb.FinderException,java.rmi.RemoteException
05/07/25 15:09:52 at com.sun.ejb.ejbql.parser.EjbQLParser.parse(EjbQLParser.java:224)
05/07/25 15:09:52 at com.sun.ejb.ejbql.EjbQLDriver.parse(EjbQLDriver.java:86)
05/07/25 15:09:52 at com.sun.ejb.sqlgen.SQLGenerator.generateSQLForEjbQLQueries(SQLGenerator.java:735)
05/07/25 15:09:52 at com.sun.ejb.sqlgen.SQLGenerator.generateSQL(SQLGenerator.java:365)
05/07/25 15:09:52 at com.evermind.server.ejb.deployment.EJBPackage.translateEjbqlQeries(EJBPackage.java:2314)
05/07/25 15:09:52 at com.evermind.server.ejb.compilation.Compilation.translateEjbqlQeries(Compilation.java:179)
05/07/25 15:09:52 at com.evermind.server.ejb.compilation.Compilation.compile(Compilation.java:219)
05/07/25 15:09:52 at com.evermind.server.ejb.compilation.Compilation.doGenerateCode(Compilation.java:271)
05/07/25 15:09:52 at com.evermind.server.ejb.EJBContainer.postInitBatch(EJBContainer.java:2279)
05/07/25 15:09:52 at com.evermind.server.ejb.EJBContainer.postInit(EJBContainer.java:2212)
05/07/25 15:09:52 at com.evermind.server.Application.postInit(Application.java:556)
05/07/25 15:09:52 at com.evermind.server.Application.setConfig(Application.java:170)
05/07/25 15:09:52 at com.evermind.server.ApplicationServer.addApplication(ApplicationServer.java:1987)
05/07/25 15:09:52 at com.evermind.server.ApplicationServer.initializeApplications(ApplicationServer.java:1926)
05/07/25 15:09:52 at com.evermind.server.ApplicationServer.setConfig(ApplicationServer.java:1482)
05/07/25 15:09:52 at com.evermind.server.ApplicationServerLauncher.run(ApplicationServerLauncher.java:92)
I am using MYSQL at the back end and I have tested this query with the database and it works fine ... because of the above error it is also unable to load the EJB package.
Not sure what is going wrong ....
When i use Select object(o) from Countries o where o.countryName like '?1', then it works but nothing returns from Database which is obvious .............
help plsss
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Error using LIKE in EJB QL (2 messages)
- Posted by: Subhankar Bhattacharya
- Posted on: July 25 2005 06:38 EDT
Threaded Messages (2)
- Error using LIKE in EJB QL by Debu Panda on July 25 2005 17:58 EDT
- Error using LIKE in EJB QL by vikas gupta on July 27 2005 08:56 EDT
-
Error using LIKE in EJB QL[ Go to top ]
- Posted by: Debu Panda
- Posted on: July 25 2005 17:58 EDT
- in response to Subhankar Bhattacharya
Subhankar,
What version opf OC4J/JDeveloper are you using ?
JDev 9.0.5/10.1.2 have only support for EJB 2.x and EJBQL like support is part of EJB 2.1.
You can try out JDev 10.1.3 Developer Preview or try deploying to a standalone version of OC4J 10.1.3. These versions have support for EJB 2.1 and hence like support for EJBQL
-Debu
http://debupanda.com -
Error using LIKE in EJB QL[ Go to top ]
- Posted by: vikas gupta
- Posted on: July 27 2005 08:56 EDT
- in response to Subhankar Bhattacharya
http://www.theserverside.com/discussions/thread.tss?thread_id=34660
check this link and this will help u alott